![\begin{displaymath}\int_1^{\sqrt{3}} \;z^2\;dz \times \cos\frac{3\,\pi}{9}=\ln \sqrt[3]{e}
\end{displaymath}](Limerick.gif)
Here's a limerick I picked up off the net a few years back:
Which, of course, translates to:
Integral z-squared dz
from 1 to the square root of 3
times the cosine
of three pi over 9
equals log of the cube root of 'e'.
And it's correct, too.
(Doug Walker, SAS Institute)